C3H8O+4.5O2→3CO2+4H2OC_3H_8O+4.5O_2\to3CO_2+4H_2OC3H8O+4.5O2→3CO2+4H2O
60 g60\ g60 g Propanol produce 44×3=132 g44\times 3=132\ g44×3=132 g of CO2CO_2CO2
100 Kg100 \ Kg100 Kg Propanol will produce 13260×100 Kg=220 Kg\frac{132}{60}\times100\ Kg =220\ Kg60132×100 Kg=220 Kg of CO2CO_2CO2
60 g60\ g60 g Propanol consume 4.5×32=144 g4.5\times 32=144 \ g4.5×32=144 g of O2O_2O2
100 Kg100 \ Kg100 Kg Propanol consume 14460×100 Kg=240 Kg\frac{144}{60}\times 100 \ Kg=240\ Kg60144×100 Kg=240 Kg of O2O_2O2 .
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