Answer to Question #10460 in Physical Chemistry for Maria
What mass of Oxygen gas would occupy a volume of 1800mL at Standard conditions? Atomic weight of oxygen is 16.
1
2012-06-05T11:26:08-0400
Standart conditions:
Temperature 273.15 K
Pressure 101.325 kPa
Using the universal gas law:
pV = nRT
or
pV = mRT/M
hence,
m(O2) = pVM/RT
where
p - pressure
V - volume
M - molar mass of O2
R - the universal gas law constant of 8.3145 m^3*Pa/(mol*K)
M(O2) = 2*16 = 32 g/mol
m(O2) = 101325 Pa * 0.0018 m^3 * 32 g/mol / ( 8.3145 m^3*Pa/(mol*K) * 273.15 K) = 2.57 g
Need a fast expert's response?
Submit order
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment