Molar mass of "N_2 O_4" = 92 grams
so we are given 1 mole of "N_2 O_4" and given that 50% dissociation takes place
"N_2 O_4\\iff 2NO_2"
1 mole 0 moles ......................initial
(1-0.5)moles 2*0.5 moles .......................final
K(equilibrium constant)="[NO_2]^2\/[N_2 O_4]"
K =12/0.5 = 2
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