Question

If 92g of N2O4 is taken in a closed vessel and heated till equilibrium is reached. At equilibrium, 50% of N2O4 is dissociated by the reaction N2O4 to 2NO2. The equilibrium constant for the reaction is:

Answer 1

Molar mass of $N_2 O_4$ = 92 grams

so we are given 1 mole of $N_2 O_4$ and given that 50% dissociation takes place

$N_2 O_4\iff 2NO_2$

1 mole 0 moles ......................initial

(1-0.5)moles 2*0.5 moles .......................final

K(equilibrium constant)=$[NO_2]^2/[N_2 O_4]$

K =1²/0.5 = 2