Question #101511
How can ionic product be determined using conductivity measurements? Explain.
1
Expert's answer
2020-01-20T05:11:18-0500

Λm=Λm0K\Lambda_m=\Lambda^0_m -K (c)1/2(c)^{1/2}

where Λm0{\displaystyle \Lambda _{m}^{0}} is known as the limiting molar conductivity, K is an empirical constant and c is the electrolyte concentration. (Limiting here means "at the limit of the infinite dilution".)


so α\alpha (dissociation constant) can be calculated by formula Λ\Lambda m/Λm0_m/\Lambda_m^0

let's us take a example :

AB(s) \leftrightarrow A+(aq) + B+ (aq)

C 0 0 ......initial

C - Cα\alpha Cα\alpha Cα\alpha .......final


so, Solubility product = [A+][B+] = C2*α2\alpha^2

where C is the concentration and α\alpha is the dissociation constant which can be calculated from the above formula.


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Comments

DEEPAK SINGH
13.04.20, 09:29

This is complete answer

DEEPAK SINGH
13.04.20, 09:27

This is complete answer

Assignment Expert
02.04.20, 16:11

Dear Anjali, This is complete answer.

Anjali
31.03.20, 20:55

Is it sufficient for 5 marks question???

Assignment Expert
17.03.20, 15:45

Dear Biju Roy This is complete answer.

Biju Roy
14.03.20, 10:24

Is this the complete ans

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