Calculate the moles of kcl required to produce 10 moles of cl2 by the reaction with kclo3?
The balanced chemical reaction is "KClO_3 + 5KCl + 3H_2SO_4\\to 3Cl_2 + 3K_2SO_4 + 3H_2O"
as we can see from the reaction that the ratio of stochiometric coefficient of KCl and chlorine is 5:1 so
for every 3 moles of chlorine produced 5 moles of KCl is required
so, for 1 moles of Cl2 produced 5/3 moles of KCl is required
to produce 10 moles of Cl2 we need (5/3)*10 moles of KCl
For producing 10 moles of chlorine gas we need 50/3 moles of KCl
Comments
Leave a comment