Question #223802
An experiment of decomposition potential of potassium chlorate(V). The equation
MnO (catalyst)
2KCIO, --> 2KCI + 30₂
Given the total volume of oxygen gas released is 37cm3 what is the number of moles of gas of oxygen?
1
Expert's answer
2021-08-09T06:22:04-0400

Solution:

At STP, one mole of any gas occupies a volume of 22400 cm3.

Therefore,

(37 cm3 O2) × (1 mol / 22400 cm3) = 0.00165 mol O2


Answer: 0.00165 mol O2

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