Question

How much heat is absorbed by a sample of metal with a mass of 40.7 g, whose temperature raises from 20.0°C to 32.4°C, with a specific heat capacity of 0.472 J/g°C?

Answer 1

Q=C x m x deltaT

deltaT = 32.4 - 20.0 = 12.4

Q = 0.472 x 40.7 x 12.4 = 238.2 J