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If 16.41 mL of aqueous NaOH is required to neutralise 20 mL of potassium hydrogen phthalate solution described in question 4 above, what is the molarity of the aqueous sodium hydroxide? Show your calculations as required below:


a- Calculate the number of moles of KHC8H4O4 used in the titration.

b- Using the balance reaction equation, find the number if moles of NaOH that reacted.

c- Calculate the molarity of the NaOH solution.


Find Unknown compound and explain?

IR data: IR Spec Bands detected - 1700, strong

carbonyl group, C=O bond

Mass Spectrometry information:

Base peak- 28, M+- 160, No M+2,

HNMR :

17 peaks

septet peak 1-6 : 4-3.8ppm

quartet peak 7-11: 3.2-3 ppm

sextet peak 11-17: 1.2- .8 ppm


Why 5d is less in energy than 4f in lanthanides?



what is the formula for Magnesium tetrahydrate?


CO (g) + H2 (g)C (s) + H2O (g) ∆H = -131 kJ.mol-1

Explain how and why the equilibrium position and the concentration of H2 would change if:

a) more carbon is added.

b) the concentration of CO is increased.

c) the pressure inside the container is increased.

d) the temperature is lowered.



Draw stereoisomers that possible for 2,3-Diamino-2,3-pentanediol


The results of a titration experiment were as follows:

 Volume of aqueous NaOH pipetted into the conical flask = 10.00 ml

 Average volume of dilute HCI added from the burette to reach the

endpoint = 12.54 mL.

 Molarity of the dilute HCI = 1.196 M


1- Calculate the number of moles of HCI added during the titration.

-What is the number of moles of NaOH that has reacted during the titration?

-What is the molarity of the aqueous NaOH?


What is the fate of Fe, Mn, Cu, and Mo micronutrients in soils that are rich or low in macronutrients content, as well as their availability to plants in such soils?                    (04)




Q.No.3. How do soils with varying microbial characteristics control the bioavailability and mobility of Fe, of Zn, B, and Mn to various plants?  


The mass of calcium carbonate in a 0.125 g stick of chalk is determined by dissolving the chalk in 50.0 mL of 0.20 M HCl and then titrating any excess HCl with a standardized solution of KOH. A volume equal to 32.12 mL of 0.250 M KOH is required to reach the endpoint.

A) How many millimoles of the excess HCl was back-titrated?


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