Moles of C6H12
"n(C_6H_{12})=\\frac{m}{M} =\\frac{0.47}{84.16} = 0.00558 mol" Energy absorbed by calorimeter:
"q = c_{cal}\\times \\Delta T = 4.716\\times (29.6-25)=21.69 kJ"
"\\Delta_r H = -q"
"\\Delta _r H = \\frac{-q}{n} = \\frac {-21.69 kJ}{0.00558 mol} =- 3887.74 \\frac{kJ}{mol}"
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