Molecular formular of cefdinir is "C_{14}H_{13}N_5O_5S_2"
Mollar mass = "395.4 \\frac{g}{mol}"
"n(cefdinir)=\\frac{m}{M} = \\frac{150 g}{395.4\\frac{g}{mol}}=0.379 mol"
As one molecule of sefdinir contains 2 atoms of S then n(S)= 2*0.379 mol = 0.758 mol
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