Answer to Question #95089 in Organic Chemistry for abe

Question

What is the mass of 2.40 ×1022 molecules of NaOH (Molar mass = 40.0 g/mol)?

Answer 1

n(NaOH) = N(NaOH) / N_A = 2.40 × 10²² / 6.02 × 10²³ mol^-1 = 0.0399 mol.

m(NaOH) = n(NaOH) × M(NaOH) = 0.0399 mol × 40 g/mol = 1.596 g ≈ 1.60 g.