Answer to Question #94096 in Organic Chemistry for Enobong

Question

consider compound A=2 chloro 2 methy butane, C= chloro protane. 1 which of the compound will readily undergo dehydrochlorination (2) what informs your answer?

Answer 1

Dehydrochlorination reaction proceeds most actively in the molecules with high numbers of substitutes around carbon atom which linked with a chlorine atom. Such structure makes final alkene molecule more stable and lowers the activation energy needed to begin the reaction. In case A, chlorine atom linked with tertiary carbon, in case C - with primary carbon. So the 2-chloro-2-methylbutane will be more active towards dehydrochlorination (as it has more substitutes around the carbon atom, which is connected to chlorine atom) than chloropropane.