a) deltaH(Al2O3)=-1675.5 kJ/mol,
deltaH(Fe2O3)=-824.2 kJ/mol,
deltaH(reaction)=deltaH(Al2O3)-deltaH(Fe2O3)=-1675.5+824.2=-851.3kJ/mol
b)n(Fe2O3)=m/M=40/159.7=0.25 mol,
deltaH=n*deltaH(reaction)=0.25*851.3=212.8 kJ
c) Q=c(water)*m(water)*(t2-t1), t2= t1+(Q/c(water)*m(water))= 48.4 C
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