a) To calculate heat trransferred to water we should use the formula:
q = cmΔT
where c (for water) = 4.184 J/mol*K
m - mass of water
m = d*V = 1g/ml *750 ml = 750 g
ΔT = 55.6 - 18.1 = 37.5 0C
so, q = 4.184*750*37.5 =117675 J = 118 kJ
b) Calculate the mass of candle which was burned:
m = 42.3 - 38.3 = 4
Energy transferrred per garm of paraffin wax is :
ΔH =-q/m = -118 kJ/4 g = -29.5 kJ/g
c) Calculate moles of wax paraffin (C25H52)
n = m/M = 4/352.68 = 0.0113 mol
ΔH = -q/n = -118 kJ/0.0113 mol = -10442 kJ/mol
d) Percentage difference = |ΔH(theoretical)| - |ΔH(actual)|/ |ΔH(theoretical)| *100% = |-42|-|-29.5|/|-42| *100% = 29.8%.
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