Question

If 3.50 grams of neon gas is at a temperature 298 K and pressure of 722 mm Hg, what is the volume?

Answer 1

Answer on Question #82505, Chemistry/ Organic Chemistry

If 3.50 grams of neon gas is at a temperature 298 K and pressure of 722 mm Hg, what is the volume?

Solution

To answer this question we should use Ideal Gas Law

$$\mathrm{PV} = \mathrm{nRT}$$ $$P = 722 \mathrm{mmHg} = 722 \times 133.3 \mathrm{Pa} = 96242.6 \mathrm{Pa}$$ $$T = 298 \mathrm{K}$$ $$R = 8.134 \mathrm{m}^3 \cdot \mathrm{Pa} / \mathrm{K} \cdot \mathrm{mol}$$ $$n = \mathrm{m} / \mathrm{M};$$ $$n(\mathrm{Ne}) = 3.50 \mathrm{g} / 20 \mathrm{g} / \mathrm{mol} = 0.175 \mathrm{mol}$$ $$\therefore V = \frac{nRT}{P} = \frac{0.175 \mathrm{mol} \times 8.314 \ \frac{\mathrm{m}^3 \mathrm{Pa}}{\mathrm{K} \ \mathrm{mol}} \times 298 \ \mathrm{K}}{96242.6 \ \mathrm{Pa}} = 0.0045 \ \mathrm{m}^3$$

Answer: $0.0045 \ \mathrm{m}^3$

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