Question

a swimmer dives into a pool 10m deep.calculate the absolute pressure there (density of water = 99kg/m3,g=9.81m/s2.atmospheric pressure =101.325kgpa

Answer 1

Question #78166:

a swimmer dives into a pool 10m deep. calculate the absolute pressure there (density of water = 99kg/m3*, g=9.81m/s2. atmospheric pressure =101.325kgpa

Solution:

*Let's correct the density of water to 997 kg/m3 (at 25°C).

Absolute pressure:

$P_{abs} = P_{water} + P_{atm}$, where $P_{water}$ – pressure of layer of water (Pa), $P_{atm}$ – atmospheric pressure (Pa);

$P_{water} = \rho \cdot H \cdot g$, where $\rho$ – density of water (kg/m³), $H$ – height of liquid column or depth (m);

$P_{abs} = \rho \cdot H \cdot g + P_{atm} = 997 \cdot 10 \cdot 9.81 + 101325 = 199130.7 \, [\mathrm{Pa}] = 199.1307 \, [\mathrm{kPa}]$

Answer: 199.1307 kPa