Question

What is the molarity of the acetic acid solution if 25.7 mL of a 0.240 M KOH solution is required to titrate 29.0 mL of a solution of HC2H3O2?
HC2H3O2(aq)+ KOH(aq)→ H2O(l)+ KC2H3O2(aq)
Express your answer with the appropriate units.

Answer 1

Answer on Question #77881, Chemistry / Organic Chemistry

Question:

What is the molarity of the acetic acid solution if 25.7 mL of a 0.240 M KOH solution is required to titrate 29.0 mL of a solution of HC₂H₃O₂?

$$\mathrm{HC_2H_3O_2(aq)} + \mathrm{KOH(aq)} \rightarrow \mathrm{H_2O(l)} + \mathrm{KC_2H_3O_2(aq)}$$

Express your answer with the appropriate units.

Solution:

Amount of KOH: 0.240 · 0.0257 = 0.006168 mol

Amount of HC₂H₃O₂: 0.006168 mol

Molarity of HC₂H₃O₂: 0.006168 / 0.0290 = 0.2127 mol/L = 0.2127 M

Answer:

0.2127 mol/L = 0.2127 M

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