Question

temperature coefficient of a reaction Y = 4, rate of reaction at 40 degree C is 0.5 mole/l.sec, what will be the rate of reaction at 80 degree celsius?

Answer 1

Answer on Question #77059, Chemistry / Organic Chemistry

Question:

Temperature coefficient of a reaction $\gamma = 4$, rate of reaction at 40 degree Celsius is 0.5 mol/(l·s), what will be the rate of reaction at 80 degree Celsius?

Solution:

The Van 't Hoff rule for the rate of reaction:

$$r_2 = r_1 \cdot \gamma^{\frac{T_2 - T_1}{10}}, \text{ where}$$ $$r_1 - \text{rate of reaction at temperature } T_1$$ $$r_2 - \text{rate of reaction at temperature } T_2$$ $$\gamma - \text{temperature coefficient of a reaction}$$

So:

$$r_2 = 0.5 \cdot 4^{\frac{80 - 40}{10}} = 0.5 \cdot 4^4 = 128 \text{ mol/(l·s)}$$

Answer:

128 mol/(l·s)

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