Question

The figure below shoes the formation of the mercurinium intermediate fro the addition of mercuric acetate to an alkene. There are two ways by which water can attack the intermediate. Draw the mechanism for both ways by using curved arrows to represent electron flow.

H3C/\\/\CH3 Hg(CH3COO)2

Answer 1

Answer on question # 76222

\begin{array}{c} \mathrm{CH_3 - \underset{H}{\overset{=} \underset{H}{\overset{=} \mathrm{C} - \mathrm{CH_3} + \mathrm{Hg}(\mathrm{OAc})_2}}} \end{array} \ce{ \begin{array}{c} \phantom{CH_3-CH-CH_3} \\ \phantom{CH_3-CH-CH_3} \\ \phantom{CH_3-CH-CH-CH_3} \\ \phantom{CH_3-CH-CH-CH_3} \\ \phantom{CH_3-CH-CH-CH-CH_3} \\ \phantom{CH_3-CH-CH-CH-CH_3} \end{array} \quad \ce{ \begin{array}{c} \phantom{CH_3-CH-CH_3} \\ \phantom{CH_3-CH-CH-CH_3} \\ \phantom{CH_3-CH-CH-CH-} \end{array} \ce{ \begin{array}{c} \phantom{CH_3-CH-CH_3} \\ \phantom{CH_3-CH-CH-CH_3} \\ \phantom{CH_3-CH-CH-CH-} \end{array} \ce{ \begin{array}{c} \phantom{CH_3-CH-CH-CH_3} \\ \phantom{CH_3-CH-CH-CH-} \end{array} $$\ce{ \begin{array}{c} \phantom{CH_3-CH-CH-CH-} \\ \phantom{CH_3-CH-CH-CH-} \\ \phantom{CH_3-CH-CH-CH-} \end{array} }$$ $$a = b$$ $$\ce{ \begin{array}{c} \phantom{CH_3-CH-CH-CH-} \\ \phantom{CH_3-CH-CH-CH-} \\ \phantom{CH_3-CH-CH-CH-} \end{array} } \quad \ce{ \begin{array}{c} \phantom{CH_3-CH-CH-CH-} \\ \phantom{CH_3-CH-CH-CH-} \\ \phantom{CH_3-CH-CH-CH-} \end{array} }$$

(b)