Question

in an IR explanation of cyclohexanol there are CH2 groups in the ring and that in the IR spectrum was at about v= 1454cm-1 so how will I say that will I say a sharp, medium band at v=1454cm-1 which illustrates v(C-H) bend of the CH2 groups of cyclohexanol or a sharp,medium band at v=1454cm-1 which illustrates v(CH2) bend of cyclohexanol?

Answer 1

The two primary modes of vibration are stretching and bending

Stretching modes are typically of higher energy than bending modes

Stretching modes are often divided into two a symmetric and asymmetric stretch; the asymmetric stretch is usually of higher energy

CH2 bending modes at 1465 cm-1

In case of cyclohexanol CH2 group show sharp medium bending mode of vibration. Cyclohexanol is cyclic system it show a bending sharp medium band at $1454~\mathrm{cm}^{\wedge}$ . In simple alkane bending at 1465 $\mathrm{Cm}^{\wedge}$ but in cyclic strain system frequency of band decrease it show at $1454~\mathrm{Cm}^{\wedge}$ .

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