Question #73138

How to derive ideal gas law using Charle's and Boyle's law?

Expert's answer

#73138

- How to derive Ideal gas law using charle's & Boyle's law?

Sol: Ideal gas equation,


V1p(Boyle’s law)(i)V \propto \frac{1}{p} \quad \text{(Boyle's law)} \quad \cdots (i)VT(Charle’s law)(ii)V \propto T \quad \text{(Charle's law)} \quad \cdots (ii)Vn(Avogadro’s law)(iii)V \propto n \quad \text{(Avogadro's law)} \quad \cdots (iii)


Combining (i), (ii) & (iii)


VnTpV \propto \frac{nT}{p}PVnTP V \propto nTPV=nRTP V = nRT


Where,

R=R = universal gas constant

R=8.314ft2mol12R = 8.314 \frac{\text{ft}^2 \text{mol}^{-1}}{2}

where PP' (pressure) is in Pa\text{Pa} or Nm2\text{Nm}^2

VV' in m3\text{m}^3

R=0.0821 atm lit/mol\cdotpKR = 0.0821 \text{ atm lit/mol·K}

R=1.987 cal/mol K1R = 1.987 \text{ cal/mol K}^{-1}

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