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Answer to Question #72525 in Organic Chemistry for paul
Question #72525
What is the mass of the solute present in 2 liters of a 3.5 M Fe2O3 solution?
Expert's answer
Please note that the Fe2O3 is not soluble in any solvent.
Let’s imagine that this solution does really exist…
Amount of Fe2O3: 3.5 ∙ 2 = 7 mol
Mass of Fe2O3: 159.69 ∙ 7 = 1117.83 g
Answer:
1117.83 g
Let’s imagine that this solution does really exist…
Amount of Fe2O3: 3.5 ∙ 2 = 7 mol
Mass of Fe2O3: 159.69 ∙ 7 = 1117.83 g
Answer:
1117.83 g
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