The glucose molecule has an open as opposed to
cyclic and unbranched backbone of six carbon atoms, C-1 through C-6; where C-1 is part of an
aldehyde group H(C=O)-, and each of the other five carbons bears one hydroxyl group -OH. The remaining
bonds of the backbone carbons are satisfied by
hydrogen atoms -H.Each of the four carbons C-2 through C-5 is
chiral, meaning that its four bonds connect to four different substituents. In D-glucose, these four parts must be in a specific three-dimensional arrangement. Namely, when the molecule is drawn in the
Fischer projection, the hydroxyls on C-2, C-4, and C-5 must be on the right side, while that on C-3 must be on the left side.
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