Question

Calculate the volume of sebacoyl chloride required to prepare a 0.19 M solution of sebacoyl chloride in 21.6 ml cyclohexane. The molecular weight of sebacoyl chloride is 239.14 g/mol and the density is 1.12 g/ml ?

Answer 1

If C – concentration of the solution (M), V – volume of the solution (ml), x – chemical amount of sebacoyl chloride (mmole) then:

C = x/V;
C = 0,19 M;
V = V (cyclohexane) + V(sebacoyl chloride)*= 21,6 + 239,14*x/1,12*1000;
0,19 = x/ (21,6 + 239,14*x/1,12*1000);
x = 4,28 mmole;
V (sebacoyl chloride) = 239,14*4,28/1,12*1000 = 0,91 (ml).
*We consider that the volume of final solution is equal to the sum of two mixing liquids (what in general case is not true).