Question

The question is one working out the equilibrium expression for some acids.

Citric Acid (H3C6H5O7)
Ka = 7.1x10-4

Answer 1

Question #69045, Chemistry / Organic Chemistry

The question is one working out the equilibrium expression for some acids.

Citric Acid (H₃C₆H₅O₇)

Ka = 7.1×10⁻⁴

Answer :

Citric Acid (H₃C₆H₅O₇) – weak triprotic acid. Dissociation equation

$$\mathrm{H_3C_6H_5O_7} \, (\mathrm{aq}) + \mathrm{H_2O} \, (\mathrm{l}) = \mathrm{H_3O^+} \, (\mathrm{aq}) + \mathrm{H_2C_6H_5O_7^-} \, (\mathrm{aq})$$ $$K_a = \frac{[H_2C_6H_5O_7^-][H_3O^+]}{[H_3C_6H_5O_7]}$$