Answer to Question #65657 in Organic Chemistry for Jamikeca Norris

Question

The half-life of the radioisotope carbon-14 is 5730 years. How much C-14 will be left after 3 half-lives, if the initial amount is 100.0 g?

Answer 1

Solution:
We find the part remaining after 3 half-lives:
(1/2)3 = 0.125
We find how much is left:
100.0 g x 0.125 = 12.5 g remain

Answer: 12.5 g C-14 will be left after 3 half-lives