Question

A 26.4-g iron rod, initially at 19.6°C, is submerged into an unknown mass of water at 68.2°C, in an insulated container. The final temperature of the mixture upon reaching thermal equilibrium is 64.6°C. What is the mass of the water?

Answer 1

Answer on Question #63679 - Chemistry - Organic Chemistry

Question

A 26.4-g iron rod, initially at 19.6°C, is submerged into an unknown mass of water at 68.2°C, in an insulated container. The final temperature of the mixture upon reaching thermal equilibrium is 64.6°C. What is the mass of the water?

Solution:

Q₁ = cₕₑ*mₕₑ*ΔT₁

Q₂ = cₕ₂₀*mₕ₂₀*ΔT₂

Q₁ = -Q₂

mₕ₂₀ = -(cₕₑ*mₕₑ*ΔT₁)/(cₕ₂₀*ΔT₂) = -(444*26.4*10⁻³*45)/(4187*(-3.6)) = 35*10⁻³ kg = 35g

Answer: 35g

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