Question #61567

What is the concentration of NO gas at equilibrium if you mix 0.20 mol of N 2 and 0.15 mol of O 2 in a 1.0 L

container at 2000 °C? The K c for the reaction at 2000 °C is .

N 2 + O 2 > 2NO

Expert's answer

Question #61567 – Chemistry – Organic Chemistry

Question

1. What is the concentration of NO gas at equilibrium if you mix 0.20 mol of N2 and 0.15 mol of O2 in a 1.0 L container at 2000 °C? The Kc for the reaction at 2000 °C is .

N2 + O2 -> 2NO

Solution

Solution is difficult because KcK_c is not given by customer.


Kc=[NO]2/([N2][O2])K_c = [NO]^2 / ([N_2][O_2])


If x mol of N2 react with O2


Kc=[2x]2/[0.2x][0.15x]K_c = [2x]^2 / [0.2 - x][0.15 - x](Kc4)x20.35Kcx+Kc0.03=0(K_c - 4) * x^2 - 0.35K_c x + K_c * 0.03 = 0x=(4Kc+(0.3524(Kc4)Kc0.03)0.5)/(2(Kc4))– typical solution of quadratic equationx = (4 - K_c + (0.35^2 - 4(K_c - 4) * K_c * 0.03)^{0.5}) / (2(K_c - 4)) \quad \text{– typical solution of quadratic equation}[NO]=2x=2(4Kc+(0.3524(Kc4)Kc0.03)0.5)/(2(Kc4))[NO] = 2x = 2 * (4 - K_c + (0.35^2 - 4(K_c - 4) * K_c * 0.03)^{0.5}) / (2(K_c - 4))


Answer: [NO]=2(4Kc+(0.3524(Kc4)Kc0.03)0.5)/(2(Kc4))[NO] = 2 * (4 - K_c + (0.35^2 - 4(K_c - 4) * K_c * 0.03)^{0.5}) / (2(K_c - 4))

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