Question

1) In hydrogen peroxide (H2O2) the ratio of masses of H:O is X:64,Find X ?
2) If the molecular mass of CH3CO2 is 'M' ,Calculate M/20?
3) In H2C2O4 the ratio of masses of C:O is 3:y,Find y ?
4) In the formation of water 1gm of H combines with y gms of O.Calculate y ?

Answer 1

Answer on Question #44322 – Chemistry – Organic Chemistry

Questions

1) In hydrogen peroxide (H₂O₂) the ratio of masses of H:O is X:64, Find X?

2) If the molecular mass of CH₃CO₂ is 'M', Calculate M/20?

3) In H₂C₂O₄ the ratio of masses of C:O is 3:y, Find y?

4) In the formation of water 1 gm of H combines with y gms of O. Calculate y?

Solution

1) Molar mass of H is 1 g/mol and molar mass of O is 16 g/mol, so we can write the proportion:

$$2 \times 1 \text{ g/mol (H)} - 2 \times 16 \text{ g/mol (O)}$$ $$X (H) - 64 (O),$$

whence

$$X = (2 \times 64) / (2 \times 16) = 4$$

2) Molar mass of C is 12 g/mol, molar mass of H is 1 g/mol and molar mass of O is 16 g/mol, so

$$M = 2 \cdot 12 \text{ g/mol} + 3 \cdot 1 \text{ g/mol} + 2 \cdot 16 \text{ g/mol} = 59 \text{ g/mol}$$ $$M / 20 = 59 / 20 = 2.8 \text{ g/mol}$$

3) Molar mass of C is 12 g/mol and molar mass of O is 16 g/mol, so we can write the proportion:

$$2 \times 12 \text{ g/mol (C)} - 4 \times 16 \text{ g/mol (O)}$$ $$3 (C) - y (O),$$

whence

$$y = (4 \times 16 \times 3) / (2 \times 12) = 8$$

4) Molar mass of H is 1 g/mol and molar mass of O is 16 g/mol, molecular formula of water is H₂O, so we can write the proportion

$$2 \times 1 \text{ g/mol (H)} - 16 \text{ g/mol (O)}$$ $$1 \text{ g (H)} - y \text{ g (O)},$$

whence

$$y = (16 \times 1) / 2 = 8$$

Answers:

1) $X = 4$

2) $M / 20 = 2.8$

3) $y = 8$

4) $y = 8$

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