Question

calculate the empirical formula of a compound whose percentage composition is : C=21.9% , H=4.6% , Br=73.4% ?

Answer 1

Answer on Question #42199, Chemistry, Organic Chemistry

Question:

calculate the empirical formula of a compound whose percentage composition is $\div$ C=21.9%, H=4.6%, Br=73.4% ?

Solution:

The relative numbers of atoms will be:

$$\begin{array}{l} W\% (C) / A_r \div W\% (H) / A_r \div W\% (Br) / A_r \\ 21.9 / 12 \div 4.6 / 1 \div 73.4 / 80 \\ 1.83 \div 4.6 \div 0.92 \\ \end{array}$$

Divide by lowest number (0.92):

$$1.99 \div 5 \div 1$$

Therefore simple ratio is:

$$2 \div 5 \div 1$$

The empirical formula of the compound is $\mathbf{C}_2\mathbf{H}_5\mathbf{Br}$

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