Question

2. How much KClO3 must be heated to obtain 2.50 gram of oxygen?

Answer 1

Answer on Question #41666, Chemistry, Organic Chemistry

Question:

How much KClO₃ must be heated to obtain 2.50 gram of oxygen?

Answer:

The equation of this reaction:

$$2 \mathrm{KClO_3} \rightarrow 2 \mathrm{KCl} + 3 \mathrm{O_2}$$

For solving this question we can use proportion:

Molecular mass of KClO₃ = 122.5 * 2 = 245

Molecular mass of O₂ = 32 * 3 = 96.

Suppose that x is mass of KClO₃.

So, we get the proportion: x/245 = 2.50g/96

x = 6.38g of KClO₃

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