Answer to Question #336293 in Organic Chemistry for Maddey Duke

Question

How many moles of nitrogen are in 72.0 g of nitrous oxide n20

Answer 1

Solution:

The molar mass of nitrous oxide (N₂O) is 44.013 g/mol

Therefore,

Moles of N₂O = (72.0 g N₂O) × (1 mol N₂O / 44.013 g N₂O) = 1.6359 mol N₂O

N₂O → 2N

According to stoichiometry:

1 mol of N₂O contains 2 mol of N

Thus, 1.6359 mol N₂O contain:

(1.6359 mol N₂O) × (2 mol N / 1 mol N₂O) = 3.2718 mol N = 3.27 mol N

Moles of N = 3.27 mol

Answer: 3.27 moles of nitrogen (N)