Balance the following redox reaction in an acidic medium:
Mn2+(aq) + NaBiO3(s) → Bi3+(aq) + MnO4-(aq)
Unbalanced reaction:
Mn2+(aq) + NaBiO3(s) → Bi3+(aq) + MnO4−(aq)
Solution:
Oxidation:
Mn2+(aq) + 4H2O(l) → MnO4−(aq) + 8H+(aq) + 5e− I ×2
Reduction:
NaBiO3(s) + 6H+(aq) + 2e− → Bi3+(aq) + 3H2O(l) + Na+(aq) I ×5
2Mn2+(aq) + 8H2O(l) → 2MnO4−(aq) + 16H+(aq) + 10e−
5NaBiO3(s) + 30H+(aq) + 10e− → 5Bi3+(aq) + 15H2O(l) + 5Na+
Balanced reaction:
2Mn2+(aq) + 5NaBiO3(s) + 14H+(aq) → 2MnO4−(aq) + 5Bi3+(aq) + 7H2O(l) + 5Na+(aq)
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