Answer to Question #328685 in Organic Chemistry for Monu

Question

Calculate the formula mass of caso4. what is the molarity of caso4 in a solution containing 1.2 gram of cso4 in a volume of 50 ml how many grams of caso4 are in 50 ml of 0.086 m caso4?

Answer 1

M_r(CaSO₄) = A_r(Ca) + A_r(S) + 4*A_r(O) = 40 + 32 + 4*16 = 136 amu

n(CaSO₄) = m(CaSO₄)/M_r(CaSO₄) = 1.2/136 = 0.008826 mol

50 mL = 0.05 L

c(CaSO₄) = n(CaSO₄)/V(solution) = 0.008826/0.05 = 0.1765 M

n(CaSO₄) = c(CaSO₄)*V(solution) = 0.086*0.05 = 0.0043 mol

m(CaSO₄) = n(CaSO₄)*M_r(CaSO₄) = 0.0043*136 = 0.5848 g