In an aqueous solution at 25°C, if [H₃O⁺] = 2.4 × 10⁻⁴ M, then [OH⁻] is:
Solution:
Kw = [H3O+] × [OH−]
The value of Kw in any aqueous solution at 25°C is 1.0×10−14
Therefore,
[OH−] = Kw / [H3O+]
[OH−] = (1.0×10−14 ) / (2.4×10−4) = 4.2×10−11
[OH−] = 4.2×10−11 M
Answer: [OH−] is 4.2×10−11 M
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