Answer to Question #3142 in Organic Chemistry for mellisa

Question

For the reaction
?CH[sub]3[/sub]OH + ?O[sub]2[/sub] => ?HCO[sub]2[/sub]H + ?H[sub]2[/sub]O,& & what is the maximum amount of HCO[sub]2[/sub]H(46.0254 g/mol) which could be formed from
10.61 mol of CH[sub]3[/sub]OH (32.0419 g/mol) and13.09 mol of O[sub]2[/sub] (31.9988 g/mol)?Answer in units of g.

Answer 1

The balanced equation is
CH₃OH + O₂ --> HCO₂H + H₂O
so, only 10.61 mol of CH₃OH could react with 10.61 mol of O₂.
ν(HCO₂H) = ν(O₂) = 10.61 mol.
m(HCO₂H) = 46.0254 [g/mol] * 10.61 mol = 488.3250 g.