Question #303432

C4H8 has four isomers. A, B & Cgets reduced by KMnO4; D does not get reduced by


KMnO4. A forms an optically inactive mixture of two optically active forms in equal


amounts with acidified KMnO4 while B forms optically inactive meso form with


acidified KMnO4. Identify A, B, C & D.

Expert's answer

A = But-2-ene

B = Trans-But-2-ene

C = 2-methylpropane

D = Cyclobutane


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