Answer to Question #303432 in Organic Chemistry for Pritam

Question

C4H8 has four isomers. A, B & Cgets reduced by KMnO4; D does not get reduced by

KMnO4. A forms an optically inactive mixture of two optically active forms in equal

amounts with acidified KMnO4 while B forms optically inactive meso form with

acidified KMnO4. Identify A, B, C & D.

Answer 1

A = But-2-ene

B = Trans-But-2-ene

C = 2-methylpropane

D = Cyclobutane