Answer to Question #302685 in Organic Chemistry for sam

Question

Assignment Question

1. C4H8 has four isomers. A, B & Cgets reduced by KMnO4; D does not get reduced by

KMnO4. A forms an optically inactive mixture of two optically active forms in equal

amounts with acidified KMnO4 while B forms optically inactive meso form with

acidified KMnO4. Identify A, B, C & D. (Draw the structures of A, B, C & D with proper

explanation).

2. Assign the priority order of the following:- (Mark 1,2,3,4 according to the priority

sequence with explanation)

a) -OH, -CH2OH, -CHO, -H

b) -CHO, -CH2OH, -CH3, -OH

c) -C6H5, -CH(CH3)2, -H, -NH2

d) -CH3 , -CH2Br, -CH2OH, -CH2Cl

e) -(CH3)2CH-, -Cl, -CH2CH2CH2Br,-CH2CH2Br

Answer 1

2D)CH3 , -CH2Br, -CH2OH, -CH2Cl deu to the electrochemical series of that ions