Problem: molecular mass of acetic acid in benzene.
Solution: No matter in what solvent the substance will be diluted. The molar mass is a constant for different molecules. The molecule of acetic acid consists of Carbon, Oxygen and Hydrogen. Formula can be described as: CH3COOH
M(CH3COOH)=2⋅M(C)+4⋅M(H)+2⋅M(O)=60 g/mol
Answer: M(CH3COOH)=60 g/mol