in a laboratory,1.55g of organic compound containing C, H, and O is combusted for analysis combustion resulted in 1.45g of carbon II oxide and 0.890g of steam. what is the empirical formular of the organic compound
Mass of O2 = 2.55 - 1.45 - 0.890 = 0.21 g .
Moles of O2 = 0.21 / 32 = 0.006
Moles of CO2 = 0.032
Moles of H2O= 0.890 / 18 = 0.049444
Then find molar ratio of CO2 and H2O.
So, ratio is 2 x : y =
moles of CO2 / moles of H2O .
Where x and y are atomicity of atom of c and H.
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