Answer to Question #286205 in Organic Chemistry for Spencer

Question

The measured integration trace gives the ratio 0.90 to 0.45 to 2.70 to 1.35 for the peak at &= 1.52 , 1.39 , 1.21 and 0.93 , respectively. Use the table below to answer the following questions.

• chemical shift (ppm) 0.5-5.0 and Description of H atom is ROH.
• chemical shift (ppm) 0.7-1.3 and description of H atom is RCH3.
• chemical shift (ppm)1.4-1.7 and description of H atom is R3CH.
• chemical shift (ppm) 1.2 -1.4 and description of H atom is R2CH2.
• chemical shift (ppm) is 2.1-2.6 and the description of H atom is RCH2CO.
• chemical shift (ppm) is 3.1-4.2 and description of H atom is RCH2Br or RCH2CI.
• chemical shift (ppm) is 9.0 -10.0 and the description of H atom is RCOH.
• chemical shift (ppm) is 10.0-12.0 and the description of H atom is RCOOH

Questions:

e) what can be deduced from the single peat at & = 1.21 and it’s integration value? ( 3 marks)

f) give a possible structure for compound Z. (1mark

Answer 1

(5-0.5)(12-10)

= 9