Question

A sample of lime CaO weighing 69g prepared by heating 131 g of limestone CaCO3 Calculate the yield of reaction

Answer 1

CaCO$_3$ -> CaO + CO$_2$

Theoretical yield = 131 g $CaCO_3 \times \frac{1 \space mol\space CaCO_3}{100.09g} \times \frac{1 \space mol\space CaO}{1 \space mol CaCo_3} \times \frac{56.08\space g}{1 \space mol}$

Theoretical yield = 73.4 g

% yield = $\frac{69 g }{73.4 g}\times100$

% yield = 94%