Answer to Question #27964 in Organic Chemistry for Morgan

Question

what mass of FeCl3 is required to prepare 100mL of 0.250 M FeCl3 solution?

Answer 1

To calculate the amount of FeCl₃, we can use the formula:
C_m = n(FeCl₃)/V_solution
Where
C_m - molar concentration
n - amount in moles
V - volume of solution
n(FeCl₃) = C_m * V_solution
n(FeCl₃) = 0.250 M * 0.1L = 0.025 moles
To calculate the mass of FeCl₃, we can use the formula:
m(FeCl₃) = n(FeCl₃) * M(FeCl₃)
Where
M - molar mass
n - amount in moles
M(FeCl₃) = Ar(Fe) +3*Ar(Cl)
M(FeCl₃) = 56 + 3 * 35.5 = 162.5 g/moles
m(FeCl₃) = 0.025 moles * 162.5 g/moles = 4.0625 g

So, the final answer is 4.0625 g of FeCl₃