Question

What is the volume of 0.0125M hydrogen bromide solution is required to titrate 125ml of a 0.010M calcium hydroxide solution

Answer 1

2HBr(aq) + Ca(OH)₂(s) → CaBr₂(aq) + 2H₂O(l)

Moles of $Ca(OH)_2=0.125×0.010=0.00125moles$

Moles of HBr = $0.00125×2=0.0025moles$

Volume of HBr=$\frac{0.0025}{0.0125}=0.2litres =200ml$