Answer to Question #273274 in Organic Chemistry for Oliver

Question

Use Hess’s Law to determine the molar enthalpy of carbon monoxide when it reacts with hydrogen as shown below. 

4 CO(g)  +  8 H2(g)  →  3 CH4(g)  +  CO2(g)  +  2 H2O(l)4 CO(g)  +  8 H2(g)  →  3 CH4(g)  +  CO2(g)  +  2 H2O(l)C  +  ½ O2(g)  →  CO(g)   C  +  ½ O2(g)  →  CO(g)    ΔH°f  =  −110.5 kJ ΔH°f  =  -110.5 kJ 
CO(g)  +  ½ O2(g)  →  CO2(g)CO(g)  +  ½ O2(g)  →  CO2(g)ΔH°f  =  −282.9 kJ ΔH°f  =  -282.9 kJ 
H2(g)  +  ½ O2(g)  →  H2O(l)H2(g)  +  ½ O2(g)  →  H2O(l)ΔH°f  =  −285.8 kJΔH°f  =  -285.8 kJ
C  +  2 H2(g)  →  CH4(g)  C  +  2 H2(g)  →  CH4(g)  ΔH°f  =  −74.8 kJ

Answer 1

The answer to your question is provided in the image: