The leachate pond consists of tropic acid at a concentration of 3.5 x 10-4 M. If the combustion reaction in d(i) releases -1215kJ, calculate the temperature change of the pond assuming that the pond has a volume of 15000L, density of 1080g/L and its specific heat is the same as pure water.
Mass = 1500×1080=1620000g=1620kg
The specific heat capacity of water is 4,200 Joules per kilogram per degree Celsius (J/kg°C).
Hear {Q} = -1215kJ
Q= mc∆T
"\u2206T=\\frac{1215}{1620\u00d74200}=0.00018\u00b0c"
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