The 2.7918 g of I is in 1 litre of the solution. Calculate Cy and T of this
solution
Moles =2.7918127=0.022moles= \frac{2.7918}{127}=0.022moles=1272.7918=0.022moles
Molarity = 0.0221=0.022M\frac{0.022}{1}=0.022M10.022=0.022M
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