Answer to Question #268587 in Organic Chemistry for ysha

Question

A chemist wishes to make 5.00g of CuCl2(s) by the reaction:

CuCl2(aq) + Na2SO3(aq) + H2O(l) → CuCl(s) + Na2SO4(aq) + 2HCl(aq). How many grams of CuCl2 and of Na2CO3 should be used if the method gives an 85.0% yield, CuCl2 is to be the limiting reactant, and a 50.0% excess of Na2SO3 is to be used?

Answer 1

Mass of CuCl2 required =7.99g

Mass of Na2CO3 required =5.61g