Answer to Question #268078 in Organic Chemistry for jho

Question

Ca5(PO4)3F + 5H2SO4 = 3H3PO4 + 5CaSO4 + HF if 24.5 g Ca(PO4)3F is mixed with 89.7 g H2SO4, how much H3PO4 will form?

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Answer 1

The quantity of Ca₅(PO4)₃F:

(24.5 g) / (504.3 g/mol) = 0.0486 mol

The quantity of H₂SO₄:

(89.7 g) / (98.1 g/mol) = 0.9144 mol

The ratio of these reactants must be 1:5, so H₂SO₄ is in excess.

Therefore, the quantity of H₃PO₄ (according to balanced reaction equation):

3 * (0.0486 mol) = 0.1458 mol

The mass of H₃PO₄:

(0.1458 mol) * (98 g/mol) = 14.3 g

Answer: 14.3 g