Sketch the following galvanic cell. Identify the cathode and anode and show the direction of electron flow. Write the oxidation and the reduction half reaction.
Cu2+ (aq) + Mg (s) → Mg2+ (aq) + Cu (s)
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Expert's answer
2021-11-21T21:56:01-0500
The equation now reads: Cu2+ + Mg → Cu + Mg2+ This is called an ionic equation; it shows only the ions and atoms involved in the reaction.
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